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Used a screen shot to Google this and it turns out to be some unsolved ancient equation regarding the laws of physics. Or something that I dont understand. And have probably misrepresented here.
No boundary and initial conditions?
My work set the password to the facilities manager’s phone extension which could just be looked up in the internal directory.
This is a fucking differential equation with unknown constants, so yeah, everyone will be burning…
Maybe use c1 and c2?
The Navier Stokes equations represent the universal laws of physics that can model any fluid in the universe.
These equations have been around since almost two centuries now but we still understand very little about them. When we have a set of equations we expect the following to happen-
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Solution should exist- One should be able to solve the equations
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Solution should be unique- Given particular initial conditions, one should obtain an unique solution to the problem. For example if you and your friend pour water into a container in an identical way, keeping all parameters (pouring velocity, direction, geometry and dimensions of the container, etc) identical then you both should get the same flow pattern. Water in both the containers should behave in exactly the same way. If your friend gets air bubbles at a point then you should get them at the exact same point as well.
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Solution should be smooth- A finite change in the input should produce a finite change in the output. It should not be erratic and unpredictable.
Unfortunately, Navier Stokes equations do not satisfy any of the conditions mentioned above.
https://medium.com/@ases2409/navier-stokes-equations-the-million-dollar-problem-78c01ec05d75
There is still waiting a prize of $1 Millon solving it, fuck the Thermostat
The Navier Stokes equations represent the universal laws of physics that can model any fluid in the universe.
Clearly you’ve never had a Pan-galactic Gargle Blaster.
I got one of those between my legs, which explains why no one has ever heard of it
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One thing I remember from physics is if you have to guess, the most common answer is zero.
As a physics major this is very true. The answers are always 0, 1, or π
No e?
Usually it is e^t or something similar
Only if you are blowing shit up.
If your signal looks like f(t) = K•u(t)e^at with u(t) = {1 if t≥0, 0 else}:
- If Real(a) > 0, then your signal will eventually blow up.
- If Real(a) < 0, then you signal will not blow up. In fact, your signal will have a maximum absolute value of |K|, and it will approach zero as time goes on.
- If Real(a) = 0, it is either a complex sinusoid or a constant. In either case, it is bounded with maximum absolute value of |K|. It very much does not blow up.
So e pops up all the time in stable systems and bounded signals because the function e^at solves the common differential equation dx/dt = ax(t) with x(0)=1 regardless of the value of a, particularly regardless of whether or not the real part of a causes the solution to blow up.
Aren’t those locked with actual keys?
Easy, I just need a wire, toothpaste, bubblegum, and and a watch crystal. Problem solved!
Aren’t those locked with actual keys?
You can say that again !
Aren’t those locked with actual keys
Get off the drugs dude.
And give them to me. I want some.
Incredibly easy to bypass as well…
A nice click out of 2…
Or if you know what you are doing electrically speaking pull the thermostat off the wall and connect the cooling/heating line to common for a bit; I think it would actually be less effort
Or blast it with a hair dryer (if you want it to cool) or air duster (if you want it to heat)
Am I missing something or does the top equation knock out half the terms? It simplifies to just F = delta + deriv. of u wrt t, right?
(Assuming p =/= 0)
Wait nope some of those ps and us are different. Oh no
Because some of those are rho and mu
Also its not delta, its upside down delta called “Del” (or nabla) which is an operator like derivative but in vector feilds
This deal keeps getting worse every day 😭
Easy to solve.
Buy one of those electric hand warmers and wedge it between the two thermostats.
I like the cut of your jib! 😝
Or you could point a flamethrower at the sensor…
For less drastic response, put your hand on the sensor.
Aren’t those locked with actual keys?
Irony is, a lot of larger office building thermostats are really only there for display purposes (thermometer), not for control purposes (actually functional).
Often tenants can change the thermostat to whatever they want visually, but in the background it caps at a certain value or doesn’t change the set point at all
