Assuming there’s a floor it’d be 5 first, then 7, then 4 and 6 basically tie, followed by 2, then a million gallons later 3, and it looks like 1 is last because it’s a tiny bit higher
even if they’re no floor, they will all fill eventually. it may cause another noah’s ark situation, but what matters is that all the containers will be filled.
It’s gonna spill out and assuming there is a floor and it’s not an infinitely bottomless pit, the water will hit the floor, and the water level in the floor will rise. Keep in mind the very first thing I said was “assuming there is a floor”
Assuming there’s a floor it’d be 5 first, then 7, then 4 and 6 basically tie, followed by 2, then a million gallons later 3, and it looks like 1 is last because it’s a tiny bit higher
even if they’re no floor, they will all fill eventually. it may cause another noah’s ark situation, but what matters is that all the containers will be filled.
3/6/7 can’t be filled, the hole between 2>3 is plugged.
Assuming there’s a floor eventually water levels will rise and breach the rim. They aren’t sealed up top
The line is blocked between 2-3, so 3,6,&7 don’t get anything.
It’s gonna spill out and assuming there is a floor and it’s not an infinitely bottomless pit, the water will hit the floor, and the water level in the floor will rise. Keep in mind the very first thing I said was “assuming there is a floor”
Given enough pressure, bucket 1 will never be filled, and it will overflow to 2 and 3. Depending on the flow, 2 could be the first to fill up.
I like the explanatory drawing your provided.
4 before 6 because of the hole in 4.
2 and 3 at the same time.
I think you’re right about 4, it’s been like 20 years since I thought about how water works lol, once that hole is submerged, 4 fills, right?